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Question

If logcosxsinx+logtanxcotx+logsecxcosecx=0.Find sinxsin(π10)

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Solution

We know that loga+logb=logab. using this property:

logcosxsinx+logtanxcotx+logsecxcosecx=0

log(cosxsinx×tanxcotx×secxcosecx)=0

log(sinxcosx)2=0

sinx=cosxx=π4

So, sinx=12

Hence,

sinxsinπ10=1×42(51)=2251


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