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Byju's Answer
Standard XI
Mathematics
Fundamental Laws of Logarithms
If log ea+b/2...
Question
If
l
o
g
e
(
a
+
b
2
)
=
1
2
(
l
o
g
e
a
+
l
o
g
e
b
)
,
then relation between a and b will be
A
a
=
b
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B
a
=
b
2
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C
2
a
=
b
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D
a
=
b
3
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Solution
The correct option is
A
a
=
b
l
o
g
e
(
a
+
b
2
)
=
1
2
(
l
o
g
e
a
+
l
o
g
e
b
)
R.H.S
=
1
2
l
o
g
e
(
a
b
)
=
l
o
g
e
√
a
b
⇒
a
+
b
2
=
√
a
b
⇒
a
+
b
=
2
√
a
b
⇒
(
√
a
−
√
b
)
2
=
0
⇒
√
a
−
√
b
=
0
⇒
a
=
b
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0
Similar questions
Q.
If
log
e
(
a
+
b
2
)
=
1
2
(
log
e
a
+
log
e
b
)
then relation between
a
and
b
will be,
Q.
If
log
e
(
a
+
b
2
)
=
1
2
(
log
e
a
+
log
e
b
)
then relation between a and b will be
Q.
Let
log
e
(
a
+
b
2
)
=
1
2
(
log
e
a
+
log
e
b
)
. If
a
=
4
, then the value of
b
would be
Q.
If
log
e
(
a
+
b
2
)
=
1
2
(
log
e
a
+
log
e
b
)
,
then relation between
a
and
b
will be.
Q.
If
l
o
g
e
(
a
+
b
2
)
=
1
2
(
l
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a
+
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g
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)
,
then relation between a and b will be
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