If logelog5-2x-2-3-0- then find the value of x-

log_ e log_ 5 [ √( 2x 2+3 ) nbsp;] =0 ⇒ log_ 5 [ √( 2x+1 ) nbsp;] =1 ⇒√( 2x+1 ) =5 ⇒ x=12 Ans: 12 ...

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Derivative of Standard Functions

if logelog5...

Question

if $l o g_{e} l o g_{5} [\sqrt{2 x - 2 + 3}] = 0$ , then find the value of $x$ .

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