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B
(−∞,32)
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C
(32,1)
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D
None of these
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Solution
The correct option is B(−∞,32) If log1√2(x−1)>2.1 =2log1√2(1√2)=log1√2(1√2)2=log1√2(12)
Since base 1√2 is less than one and hence the sign of inequality is reversed. ∴x−1<12orx<32 ∴xϵ(−∞,32)