If logk A.log5 k=3, then A=
5k3
k3
125
243
logk A.log5 k=3
Using identity, logm b.logb a=logm a, we have
⇒log5 k.logk A=3
⇒log5 A=3⇒A=53
If 3a = 729, then 3a−2 =
If A+B=5 and AB=6. Find A3+B3.