If logm11>logm33, then which of the following can be the possible value of m ?
A
3
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B
6
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C
0.6
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D
1
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Solution
The correct option is C0.6 Given: logm11>logm33
Now, using the inequality property i.e. logax>logay⇒(x>y;a>1x<y;0<a<1Here logm11>logm33⇒0<m<1
Thus the possible values of m is 0.6.