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Question

If log(x2y3)=a, and logxy=b, find logx and logy.

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Solution

log(x2y3)=a(1)logxy=b(2)
Eq (1) log(x2y3)=a
2logx+3logy=a
Eq (2) log(xy)=b
logxlogy=b
Solving both the equations gives
logx=15(a+3b),logy=15(a2b)

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