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B
(0, k)
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C
(k, 1)
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D
R+
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Solution
The correct option is C (k, 1) logyk<1 case 1 : if y > 1 ⇒ k < y for logyk>0⇒k>1 which is not possible case 2 : if y < 1 ⇒ k > y and for logyk>0⇒k<1 which is true