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Question

If logx=m+n and logy=m−n, then value of log10xy2 in terms of m and n is

A
1m3n
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B
1+m+3n
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C
1+m3n
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D
1m+3n
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Solution

The correct option is D 1m+3n
Let k=log10xy2
k=log10+logx2logy (Using loga.b=loga+logb,logab=logalogb)
k=1+m+n2m+2n
k=1m+3n

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