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Question

If log0.53xx+2<0, then the number of integral values of x is

A
1
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B
2
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C
4
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D
3
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Solution

The correct option is B 2
Given that, log0.53xx+2<0For log0.53xx+2<0 to be defined3xx+2>0x3x+2<02<x<3 ....(1]log0.53xx+2<03xx+2>13xx+21>03xx2x+2>0or, 2x1x+2<0or, 2<x<12 ...(2]From (1] and (2] we getx(2,12)The integral values of x are 1 and 0.

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