If $log 2$ , $log (2^{x} - 1)$ and $log (2^{x} + 3)$ are in AP , then the value of $x$ is given by

\frac{5}{2}

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{log}_{2} 5

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{log}_{3} 5

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{log}_{5} 3

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Solution

The correct option is B ${log}_{2} 5$

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Similar questions

log 2, log (2^{x} - 1), log (2^{x} + 3)

x

log 2, log (2^{x} - 1), log (2^{x} + 3)

A . P

x

{log}_{2} (x^{3} + x^{2}) - {log}_{2} (x + 1) = 5

{log}_{2} x

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