Question

If logarithm of $32$ to the base $4$ is $\frac{m}{2}$, then $m$ is equal to

• A. $12$
• B. $7$
• C. $5$
• D. $2$

Answer 1

Answer: (C)

$5$

${\log }_{4}32=x$

$\text{In exponent form}$

$32=4^x=2^{2x}$

$2^5=2^{2x}$

$x=\frac{5}{2}=\frac{m}{2}$

$m=5$