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Question

If logm+logn=log(m+n) find the value of m in terms of n

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Solution

if log m + log n = log (m+n ),
find m in terms of n
we can write this as
log(mn) = log(m+n)
therefore
mn = m + n
subtract m from both sides
mn - m = n
Factor out m,
m(n-1) = n

divide both sides by (n-1),
m = n/(n-1)


Hope you understand!

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