Question

If LPG cylinder contains a mixture of butane and isobutane, then the amount of oxygen that would be required for combustion of $1$ kg of it will be:

• A. $1.8$ kg
• B. $2.7$ kg
• C. $4.5$ kg
• D. $3.58$ kg

Answer 1

The correct option is D $3.58$ kg

The balanced reaction for the combustion of butane is given below:

$C_4{H}_{10}+\frac{13}{2}{O}_2\to 4C{O}_2+5H_{2}O$

Moles of butane $=\frac{1\times {10}^3}{58}$
Weight of oxygen $=W_{O_2}=\frac{13}{2}\times \frac{{10}^3}{58}\times 32=3586g=3.58kg$

Hence, the correct option is $D$.