If LSA of a cube is 100 cm 2- then its side is-A- 5 cmB- 10 cmC- 25 cmD- 6 cm

The correct option is A 5 cmLSA of a cube = 4a^2, where 'a' is the side of the cube. Given, LSA= nbsp;100 cm^2 Then, 4a^2= nbsp;100 cm^2 ⇒ a^2 = 25 cm^2 ...

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Standard VI

Mathematics

Lateral surface area of a cube

If LSA of a c...

Question

If LSA of a cube is 100 cm $^{2}$ , then its side is:

5 cm

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10 cm

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25 cm

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6 cm

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Solution

The correct option is A 5 cm
$LSA of a cube = 4 a^{2}, where 'a' is the side of the cube.$

$Given, LSA = 100 {cm}^{2} Then, 4 a^{2} = 100 {cm}^{2} \Rightarrow a^{2} = 25 {cm}^{2} \Rightarrow a = \sqrt{25} cm ∴ a = 5 cm$
(Length is always positive. Hence $\sqrt{25} = - 5$ is not considered)

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If LSA of a cube is 100 cm2, then its side is:

The correct option is A 5 cmLSA of a cube=4a2,where 'a' is the side of the cube. Given, LSA=100 cm2Then, 4a2=100 cm2⇒a2=25 cm2⇒a=√25 cm∴a=5 cm (Length is always positive. Hence √25=−5 is not considered)

If LSA of a cube is 100 cm $^{2}$ , then its side is:

The correct option is A 5 cm
$LSA of a cube = 4 a^{2}, where 'a' is the side of the cube.$

$Given, LSA = 100 {cm}^{2} Then, 4 a^{2} = 100 {cm}^{2} \Rightarrow a^{2} = 25 {cm}^{2} \Rightarrow a = \sqrt{25} cm ∴ a = 5 cm$
(Length is always positive. Hence $\sqrt{25} = - 5$ is not considered)