If $m_{0}$ is the mass of isotope $\frac{16}{8} O, m_{p} a n d m_{m}$ are the masses of a proton and neutron respectively, the nuclear binding energy of the isotope is:

(m_{0} - 17 m_{n}) c^{2}

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(m_{0} - 8 m_{p}) c^{2}

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(m_{0} - 8 m_{p} - 8 m_{n}) c^{2}

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m_{0} c^{2}

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Solution

The correct option is C $(m_{0} - 8 m_{p} - 8 m_{n}) c^{2}$
$Δ m = Mass defect=mass of constituent nucleons - mass of molecule = 8 m_{p} + (16 - 8) m_{n} - m_{0}$
Binding energy = $Δ m \times c^{2} = (8 (m_{p} + m_{n}) - m_{0}) c^{2}$
Option C is correct.

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If m0 is the mass of isotope 168O,mp and mm are the masses of a proton and neutron respectively, the nuclear binding energy of the isotope is:

The correct option is C (m0 − 8mp−8mn)c2Δm=Mass defect=mass of constituent nucleons - mass of molecule=8mp+(16−8)mn−m0Binding energy =Δm×c2=(8(mp+mn)−m0)c2Option C is correct.

If $m_{0}$ is the mass of isotope $\frac{16}{8} O, m_{p} a n d m_{m}$ are the masses of a proton and neutron respectively, the nuclear binding energy of the isotope is:

The correct option is C $(m_{0} - 8 m_{p} - 8 m_{n}) c^{2}$
$Δ m = Mass defect=mass of constituent nucleons - mass of molecule = 8 m_{p} + (16 - 8) m_{n} - m_{0}$
Binding energy = $Δ m \times c^{2} = (8 (m_{p} + m_{n}) - m_{0}) c^{2}$
Option C is correct.