If m1 and m2 be the masses of two substance liberated at electrodes and E1,E2 be their respectively chemical equivalents, then m1/m2 is equal to
A
E1+E2E1−E2
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B
E1+E2E1E2
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C
E1/E2
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D
E2/E1
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Solution
The correct option is CE1/E2 E.C.E of a substance(E) is the mass(m) of ions liberated by the passage of 1A current for one second through its electrolytic solution. E=mItm=EIt
As per the given problem m1=E1It and m2=E2It Hence, m1m2=E1ItE2It