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Characteristics of Equilibrium Constant

If m1 and ...

Question

If $m_{1}$ and $m_{2}$ be the masses of two substance liberated at electrodes and $E_{1}, E_{2}$ be their respectively chemical equivalents, then $m_{1} / m_{2}$ is equal to

\frac{E_{1} + E_{2}}{E_{1} - E_{2}}

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\frac{E_{1} + E_{2}}{E_{1} E_{2}}

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E_{1} / E_{2}

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E_{2} / E_{1}

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Solution

The correct option is C $E_{1} / E_{2}$
E.C.E of a substance(E) is the mass(m) of ions liberated by the passage of 1A current for one second through its electrolytic solution.
$E = \frac{m}{I t}$ $m = E I t$
As per the given problem $m_{1} = E_{1} I t$
and $m_{2} = E_{2} I t$
Hence, $\frac{m_{1}}{m_{2}} = \frac{E_{1} I t}{E_{2} I t}$

$\frac{m_{1}}{m_{2}} = \frac{E_{1}}{E_{2}}$

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If m1 and m2 be the masses of two substance liberated at electrodes and E1,E2 be their respectively chemical equivalents, then m1/m2 is equal to

The correct option is C E1/E2E.C.E of a substance(E) is the mass(m) of ions liberated by the passage of 1A current for one second through its electrolytic solution.E=mIt m=EItAs per the given problem m1=E1Itand m2=E2It Hence, m1m2=E1ItE2Itm1m2=E1E2

If $m_{1}$ and $m_{2}$ be the masses of two substance liberated at electrodes and $E_{1}, E_{2}$ be their respectively chemical equivalents, then $m_{1} / m_{2}$ is equal to