Question

If $(m^2-3m-18)÷(m+3)=0$ then $m=?$

• A. $-6$
• B. $0$
• C. $6$
• D. None of these

Answer 1

The correct option is C $6$

We solve the given expression $\frac{m^2-3m-18}{m+3}=0$ as shown below:

$\frac{m^2-3m-18}{m+3}=0\Rightarrow m^2-3m-18=0\times (m+3)\Rightarrow m^2-3m-18=0\Rightarrow m^2-6m+3m-18=0\Rightarrow m(m-6)+3(m-6)=0\Rightarrow (m+3)(m-6)=0\Rightarrow (m+3)=0,(m-6)=0\Rightarrow m=-3,m=6$

if m=-3 denominator will be 0 so,

Hence, $m=6$.