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Question

If m=2 and n=1, then find the value of following polynomials:
3m2−12mn+4n2

A
8
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B
4
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C
10
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D
None of these
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Solution

The correct option is A 8
Let us substitute m=2 and n=1 in the given polynomial 3m212mn+4n2 as shown below:

3m212mn+4n2=3(2)2(12×2×1)+4(1)2=(3×4)24+(4×1)=1224+4=24+16=8

Hence, 3m212mn+4n2=8, if m=2 and n=1.

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