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Question

If m=2 and n=1, then find the value of following polynomials:
4m2n

A
16
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B
14
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C
13
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D
None of these
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Solution

The correct option is A 16
Let us substitute m=2 and n=1 in the given polynomial 4m2n as shown below:

4m2n=4(2)21=4×4=16

Hence, 4m2n=16, if m=2 and n=1.

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