If $m = 2$ and $n = - 2$ , find the value of $6 m^{3} + 4 n^{- 2}$

$40$

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$49$

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$42$

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$37$

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Solution

The correct option is B
$49$

Given : $m = 2$ and $n = - 2$

$6 m^{3} + 4 n^{- 2}$ = $6 (2)^{3} + 4 (- 2)^{- 2}$

= $6 \times 8 + \frac{4}{(- 2)^{2}}$

= $48 + 1$ = $49$

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Similar questions

If $m = 2$ and $n = - 2$ , find the value of $6 m^{3} + 4 n^{- 2}$

m = - 2

n = 2

6 m^{- 3} + 4 n^{2}

m = 3

n = 2

- 2 m^{3} - 3 n^{2} + 5 m^{2} n

m = 3

n = 2

2 m^{2} n^{2}

3 m^{2} - 12 m n + 4 n^{2}

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