If $m + 2 n = 5$ , expresses $5 m^{2} - 3 n - 8$ in terms of $n$ .

20 n^{2} - 103 n + 117

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n^{2} - 13 n + 156

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20 n^{2} - 117 n + 103

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2 n^{2} - 103 n + 117

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Solution

The correct option is A $20 n^{2} - 103 n + 117$
Given, $5 m^{2} - 3 n - 8$ And $(m + 2 n) = 5$
So $m = 5 - 2 n$
Then place value of $m$ will be $5 {(5 - 2 n)}^{2} - 3 n - 8$
= $5 (25 - 20 n + 4 n^{2}) - 3 n - 8$
= $125 - 100 n + 20 n^{2} - 3 n - 8$
= $20 n^{2} - 103 n - 117$

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Similar questions

m + 2 n = 5

5 m^{2} - 3 n - 8

n .

If HCF of 65 and 117 can be expressed in the form 65m+117n, find the value of m and n.

Fond the HCF of 65 and 117 and express it in the form 65n + 117n.

8 n + 20 n^{2}

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