If $m = 3 t^{2} - t$ , then the value of $t$ for which $m = 4$ is

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $- 1$
Given, $m = 3 t^{2} - t, m = 4$
Then $4 = 3 t^{2} - t$
$3 t^{2} - t - 4 = 0$
$3 t^{2} - 4 t + 3 t - 4 = 0$
$t (3 t - 4) + 1 (3 t - 4) = 0$
$(t + 1) (3 t - 4) = 0$
$∴ t = - 1$ and $t = \frac{4}{3}$

Suggest Corrections

Similar questions

V = 8 -9t if t<1

V = 8 - 2t if t > 2

Find the value of V (m/s) when t = 3.

λ_{m 1} : λ_{m 2} : λ_{m 3} = 1 : (15)^{1 / 2} : (7)^{1 / 2}

λ_{m_{1}} : λ_{m_{2}} : λ_{m_{3}} = 1 : (21)^{0.5} : (3)^{0.5}

v = (4 t^{2} + 5 t + 1) m / s

t

s = 0

t = 0

\sqrt{- 1}

\frac{[(t - 1) (2 t + 1 - i \sqrt{3}) (2 t + 1 + i \sqrt{3})]}{4}

Join BYJU'S Learning Program