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Trigonometric Ratios of Multiples of an Angle

If m = 4, n =...

Question

If $m = 4, n = 6 and k cot θ = 6 cot B + q cot C$ , then the value of $k + q$ is

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Solution

By $m - n$ $cot$ theorem:
$(m + n) cot θ = n cot B - m cot C \Rightarrow (4 + 6) cot θ = 6 cot B - 4 cot C \Rightarrow 10 cot θ = 6 cot B - 4 cot C ∴ k + q = 10 - 4 = 6$

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Trigonometric Ratios of Multiples of an Angle

Standard XII Mathematics

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