Question

If $m_A$ $g$ of metal $A$ replaces $m_B$ $g$ of metal $B$ from its salt solution and if the equivalent weights are $E_A$ and $E_B$ respectively, then the equivalent weight of A can be expressed as:

• A. $E_A=\left(\frac{m_A}{m_B}\right)\times E_B$
• B. $E_A=\frac{(m_A\times m_B)}{E_B}$
• C. $E_A=\left(\frac{m_B}{m_A}\right)\times E_B$
• D. None of the above

Answer 1

The correct option is A $E_A=\left(\frac{m_A}{m_B}\right)\times E_B$

Given in the question,
$m_A$ gm of metal A displaces $m_B$ gm of metal B
and also their equivalent masses are also given respectively as $E_a$ and $E_b$.
According to Faraday's law,
Mass of the substance liberated or dissolved by using same amount of electricity is directly proportional to their equivalent masses
$m\propto E$
So $\frac{m_A}{m_B}\propto \frac{E_A}{E_B}$
So $E_A=\left(\frac{m_A}{m_B}\right)\ast E_B$
So option (a) is correct