The given function is f(x) = (x + 1)2 + 3, x ∈ [−3, 1].
f(x) = (x + 1)2 + 3
Differentiating both sides with respect to x, we get
For maxima or minima,
Now,
So, x = −1 is the point of local minimum of f(x).
At x = −1, we have
f(−1) = (−1 + 1)2 + 3 = 0 + 3 = 3
At x = −3, we have
f(−3) = (−3 + 1)2 + 3 = 4 + 3 = 7
At x = 1, we have
f(1) = (1 + 1)2 + 3 = 4 + 3 = 7
Thus, the minimum value of f(x) is 3 and the maximum value of f(x) is 7.
∴ m = 3 and M = 7
Thus, the ordered pair (m, M) is (3, 7).
If m and M respectively denote the minimum and maximum values of f(x) = (x + 1)2 + 3 in the interval [−3, 1], then the ordered pair (m, M) = ___(3, 7)___.