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Question

If m and n are the roots of the equation x25x+3=0, find the values of
i) (m+n)2+(mn)2
ii) (m+n)3+4mn

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Solution

x25x+3=0
a=1,b=5,c=3
m+n=ba=(5)1=5
m+n=ca=31=3

i) (m+n)2+(mn)2=(m+n)2+[(m+n)24mn]
=52+524(3)
=25+2512
=5012
=38

ii) (m+n)3+4mn=(5)3+4(3)
=125+12
=137.

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