if m and n are two natural numbers and m^n=32 then n^mn=?

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Solution

$m^{n} = 32 = 2 \times 2 \times 2 \times 2 \times 2 = 2^{5} So we get m = 2 and n = 5 So n^{mn} = 5^{10}$

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if m and n are two natural numbers and m^n=32 then n^mn=?

mn= 32= 2×2×2×2×2= 25So we get m = 2 and n = 5So nmn=510

$m^{n} = 32 = 2 \times 2 \times 2 \times 2 \times 2 = 2^{5} So we get m = 2 and n = 5 So n^{mn} = 5^{10}$