If m and n are whole numbers such that n>1 and m $^{n}$ = 121, then the value of (m - 1) $^{n + 1}$ is :

No worries! We‘ve got your back. Try BYJU‘S free classes today!

121

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1000

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

14400

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D
1000

We know that 11 $^{2}$ = 121. Putting m = 11 and n = 2, we get ${(m - 1)}^{n + 1} = {(11 - 1)}^{(2 + 1)} = 10^{3} = 1000.$

Suggest Corrections

Similar questions

If m and n are whole numbers such that n>1 and m $^{n}$ = 121, then the value of (m - 1) $^{n + 1}$ is :

m

n

m^{n} = 121,

(m - 1)^{n + 1}

m

n

m^{n} = 121,

(m - 1)^{n + 1}

m^{n} = 121

{(m - 1)}^{n + 1}

m^{n} = 32

n^{m n}

Join BYJU'S Learning Program