If mcos - - -ncos - - show that m-n - - m-n tan-

From the given relation, we have m n =cos( θ α #160; ) #160; #160; cos( θ +α #160; ) #160; #160; Apply componendo and dividendo ∴ m n ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Geometrical Representation of Argument and Modulus

If mcos θ +...

Question

If $m cos (θ + α) = n cos (θ - α)$ , show that $(m - n) cot θ = (m + n) tan α$

Open in App

Solution

Suggest Corrections

Similar questions

m sin θ = n cos θ

\frac{tan θ + cot θ}{tan θ - cot θ} = \frac{n sin θ + m cos θ}{n sin θ - m cos θ} = \frac{n^{2} + m^{2}}{n^{2} - m^{2}}

m cos (θ + α) = n cos (θ - α)

tan θ . tan α = \frac{m + n}{m - n}

\frac{sin (α + β)}{sin (α - β)} = \frac{a + b}{a - b}

tan α . cot β = \frac{a}{b}

If tan(α+θ) =n tan(α-θ) show that : (n+1)sin 2θ =(n-1)sin2α

α < \frac{π}{4 (n - 1)}

tan n

α > n tan α

tan α = m / (m + 1), tan β = 1 / (2 m + 1)

α + β = π / 4

Join BYJU'S Learning Program