If m - x1 - x2 - - - x2020- then the value of - 20i-lxi - m20 is

The correct option is B 0 Let the summation be S. S = #160; ∑ _i=1^20(x_i m)20 #160; S = ∑_i=1^20x_i20 ∑_i=1^20m20 S = m m= 0 ...

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Logarithmic Differentiation

If m = x1...

Question

If $m$ = $\frac{x_{1} + x_{2} + . . . . . + x_{20}}{20}$ , then the value of $Σ_{i = l}^{20} \frac{(x_{i} - m)}{20} i s$

\frac{19 m}{20}

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\frac{1}{20}

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Solution

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Similar questions

\frac{x_{1} + x_{2} + . . . + x_{20}}{20}

\sum_{i - 1}^{20} \frac{(x_{i} - M)}{20}

M = \frac{x_{1} + x_{2} +_{20}}{20}

20 \sum i = 1 \frac{(x_{i} - M)}{20}

\frac{x_{1} + x_{2} . . . . + x_{20}}{20} = M

20 \sum i = 1 \frac{x_{i} - M}{20}

x_{1}, x_{2}, x_{3} . . . . . . . . . . . x_{20}

25

20 \sum i = 1 (x_{1} - 25) = ?

20 \sum n = 1 20 \sum m = 1 {tan}^{- 1} (\frac{m}{n}) = k π,

k

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