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Differentiation

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Question

If $M_{e}$ and $R_{e}$ be the mass and radius of earth respectively, then the escape velocity will be:

v_{e} = \sqrt{{\frac{2 G M_{e}}{R_{e}}}^{2}}

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v_{e} = \sqrt{\frac{2 G M_{e}}{R_{e}^{2}}}

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v_{e} = \sqrt{\frac{2 G M_{e}}{R_{e}}}

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v_{e} = \sqrt{\frac{3 G M_{e}}{2 R_{e}}}

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Solution

The correct option is C $v_{e} = \sqrt{\frac{2 G M_{e}}{R_{e}}}$

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