If m -0- n -0 and p -0- then both the roots of the equation mx 2- nx - p -0 areA- none of theseB- have -ve real partsC- rational numbersD- real and negative

The correct option is B have –ve real partsx=( b±√(D))/2a D=n^2 4mp n^2 (as m0 and p0), the roots of this equation will be –ve. If D0, then the roots will have ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Quantitative Aptitude

Solving Inequalities

If m >0, n >0...

Question

If m $>$ 0, n $>$ 0 and p $>$ 0, then both the roots of the equation $m x^{2} + n x + p = 0$ are

real and negative

No worries! We‘ve got your back. Try BYJU‘S free classes today!

have –ve real parts

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

rational numbers

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B have –ve real parts
$x = \frac{(- b \pm \sqrt{D})}{2 a}$

$D = n^{2} - 4 m p < n^{2}$ (as m $>$ 0 and p $>$ 0), the roots of this equation will be –ve. If D $<$ 0, then the roots will have negative real parts

Suggest Corrections

Similar questions

Q. if m>0, n>0 and p>0, then both the roots of the equation mx²+nx+p=0 are

Q. Let a > 0, b > 0 and c > 0. Then both the roots of the equation

2 a x^{2} + 3 b x + 5 c = 0

If the roots of the equation $q x^{2} + p x + q = 0$ where p, q are real, be complex, then the roots of the equation $x^{2} - 4 q x + p^{2} = 0$ are

Q. If

l, m, n

are real,

l \neq m

, then the roots of the equation

(l - m) x^{2} - 5 (l + m) x - 2 (l - m) = 0

, are

Q. If

5, - 7, 2

are the roots of

l x^{3} + m x^{2} + n x + p = 0

, then the roots of

l x^{3} - m x^{2} + n x - p = 0

are

Join BYJU'S Learning Program

If m>0, n>0 and p>0, then both the roots of the equation mx2+nx+p=0 are

The correct option is B have –ve real partsx=(−b±√D)2a D=n2−4mp<n2 (as m>0 and p>0), the roots of this equation will be –ve. If D<0, then the roots will have negative real parts

If m $>$ 0, n $>$ 0 and p $>$ 0, then both the roots of the equation $m x^{2} + n x + p = 0$ are

The correct option is B have –ve real parts
$x = \frac{(- b \pm \sqrt{D})}{2 a}$

$D = n^{2} - 4 m p < n^{2}$ (as m $>$ 0 and p $>$ 0), the roots of this equation will be –ve. If D $<$ 0, then the roots will have negative real parts