If m -0- n -0 and p -0- then both the roots of the equation mx 2- nx - p -0 areA- none of theseB- have -ve real partsC- rational numbersD- real and negative

The correct option is B have –ve real partsx=( b±√(D))/2a D=n^2 4mp n^2 (as m0 and p0), the roots of this equation will be –ve. If D0, then the roots will have ...

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Quantitative Aptitude

Solving Inequalities

If m >0, n >0...

Question

If m $>$ 0, n $>$ 0 and p $>$ 0, then both the roots of the equation $m x^{2} + n x + p = 0$ are

real and negative

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have –ve real parts

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rational numbers

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none of these

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Solution

The correct option is B have –ve real parts
$x = \frac{(- b \pm \sqrt{D})}{2 a}$

$D = n^{2} - 4 m p < n^{2}$ (as m $>$ 0 and p $>$ 0), the roots of this equation will be –ve. If D $<$ 0, then the roots will have negative real parts

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If m>0, n>0 and p>0, then both the roots of the equation mx2+nx+p=0 are

The correct option is B have –ve real partsx=(−b±√D)2a D=n2−4mp<n2 (as m>0 and p>0), the roots of this equation will be –ve. If D<0, then the roots will have negative real parts

If m $>$ 0, n $>$ 0 and p $>$ 0, then both the roots of the equation $m x^{2} + n x + p = 0$ are

The correct option is B have –ve real parts
$x = \frac{(- b \pm \sqrt{D})}{2 a}$

$D = n^{2} - 4 m p < n^{2}$ (as m $>$ 0 and p $>$ 0), the roots of this equation will be –ve. If D $<$ 0, then the roots will have negative real parts