If m is a real number then the simplified form of the expression
$(m^{- 16} \div m^{- 8} \div m^{- 6} \div m^{- 4})$ is ______

1

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m

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m^{- 2}

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m^{2}

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Solution

The correct option is C $m^{2}$
$m^{- 16} \div m^{- 8} \div m^{- 6} \div m^{- 4}$
$= m^{- 16 + 8} \div m^{- 6} \div m^{- 4}$
$= m^{- 8} \div m^{- 6} \div m^{- 4}$
$= m^{- 8 + 6} \div m^{- 4}$
$= m^{- 2} \div m^{- 4} = m^{- 2 + 4} = m^{2}$

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