If $m$ is a whole number, then for any non-zero integers $a$ and $b$
$a^{m} \div b^{m}$ =_____________

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Solution

If we are dividing two exponential numbers with the different base but the same exponent then, they can be represented as -
$a^{m} \div b^{m} = {(\frac{a}{b})}^{m}$

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m, \frac{a^{m + 1} + b^{m + 1}}{a^{m} + b^{m}}

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$a^{m} \times b^{m} = (a b)^{m}$

$a^{m} \times b^{m}$ is equal to

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B. $(a b)^{m}$

C. $(a b)^{0}$

D $((a b)^{m})^{2}$

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