If $M$ is molecular weight of solvent, $K_{b}$ is molal elevation constant, $T_{b}$ is its boiling point, $p^{o}$ is its vapour pressure at temperature $T$ and $p_{s}$ , is vapour pressure of its solution having a non-volatile solute at $T K$ , then:

\frac{p^{\circ} - p_{s}}{p^{\circ}} = \frac{Δ T_{b}}{K_{b}} \times M

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\frac{p^{\circ} - p_{s}}{p^{\circ}} = \frac{K_{b}}{Δ T_{b}} \times M

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\frac{p^{\circ} - p_{s}}{p^{\circ}} = \frac{K_{b}}{Δ T_{b}} \times \frac{M}{1000}

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\frac{p^{\circ} - p_{s}}{p^{\circ}} = \frac{Δ T_{b}}{K_{b}} \times \frac{M}{1000}

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Solution

The correct option is D $\frac{p^{\circ} - p_{s}}{p^{\circ}} = \frac{Δ T_{b}}{K_{b}} \times \frac{M}{1000}$
$\frac{P^{\circ} - p_{s}}{P^{\circ}} = \frac{n}{N}$

$= \frac{m o l a l i t y \times M}{1000}$

And molality $= \frac{Δ T_{b}}{K_{b}}$ $(∵ Δ T_{b} = K_{b} \times m)$

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If M is molecular weight of solvent, Kb is molal elevation constant, Tb is its boiling point, po is its vapour pressure at temperature T and ps, is vapour pressure of its solution having a non-volatile solute at T K, then:

The correct option is D p∘−psp∘=ΔTbKb×M1000P∘−psP∘=nN=molality×M1000And molality =ΔTbKb (∵ΔTb=Kb×m)

If $M$ is molecular weight of solvent, $K_{b}$ is molal elevation constant, $T_{b}$ is its boiling point, $p^{o}$ is its vapour pressure at temperature $T$ and $p_{s}$ , is vapour pressure of its solution having a non-volatile solute at $T K$ , then:

The correct option is D $\frac{p^{\circ} - p_{s}}{p^{\circ}} = \frac{Δ T_{b}}{K_{b}} \times \frac{M}{1000}$
$\frac{P^{\circ} - p_{s}}{P^{\circ}} = \frac{n}{N}$

$= \frac{m o l a l i t y \times M}{1000}$

And molality $= \frac{Δ T_{b}}{K_{b}}$ $(∵ Δ T_{b} = K_{b} \times m)$