If -m- is the mass of a body- -a- is amplitude of vibration- and -w - is the angular frequency then 1 - 2 ma 2 w 2 has same dimensional formula as -

The correct option is A all the aboveDimension of #160; 12ma^2w^2=ML^2 ( 1T^2 )=ML^2T^ 2 Work =F.d ( force× distance )= ( MLT^2 )× L=ML^2T^ 2 Moment ...

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Byju's Answer

Standard XII

Physics

Relating Circular Motion to SHM

If 'm' is t...

Question

If $^{'} m$ ' is the mass of a body, $^{'} a^{'}$ is amplitude of vibration, and $^{'} w^{'}$ is the angular frequency then $\frac{1}{2} {m a}^{2} w^{2}$ has same dimensional formula as :

work

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moment of force

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energy

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all the above

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Solution

The correct option is A all the above
Dimension of $\frac{1}{2} m a^{2} w^{2} = M L^{2} (\frac{1}{T^{2}}) = M L^{2} T^{- 2}$
Work $= F . d (f o r c e \times d i s t a n c e) = (\frac{M L}{T^{2}}) \times L = M L^{2} T^{- 2}$
Moment of force $= \to f \times \to r = [\frac{M L}{T^{2}}] \times L = M L^{2} T^{- 2}$
Energy = work = $M L^{2} T^{- 2}$

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If ′m' is the mass of a body, ′a′ is amplitude of vibration, and ′w′ is the angular frequency then 12ma2w2 has same dimensional formula as :

The correct option is A all the aboveDimension of 12ma2w2=ML2(1T2)=ML2T−2Work=F.d(force×distance)=(MLT2)×L=ML2T−2Moment of force =→f×→r=[MLT2]×L=ML2T−2Energy = work = ML2T−2

If $^{'} m$ ' is the mass of a body, $^{'} a^{'}$ is amplitude of vibration, and $^{'} w^{'}$ is the angular frequency then $\frac{1}{2} {m a}^{2} w^{2}$ has same dimensional formula as :