If m is the mass of an electron and c is the speed of light, the ratio of the wavelength of a photon of energy E to that of the electron of the same energy is,
A
c√2mE
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B
√2mE
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C
√2mcE
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D
√mE
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Solution
The correct option is Ac√2mE Energy of photon, E=hν=hcλPh
Where, λPh is the wavelength of a photon ⇒λPh=hcE
Wavelength of the electron, λe=h√2mE ∴λPhλe=hcE×√2mEh=c√2mE