If $m$ is the slope of a line parallel to $3 x + 4 y + 7 = 0$ .Find the value of $16 m^{2}$

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Solution

Slope $= m = \frac{- c o - e f f i c i e n t o f x}{c o - e f f i c i e n t o f y} = \frac{- 3}{4}$
$16 m^{2} = 16 \times \frac{- 3}{4} \times \frac{- 3}{4} = 16 \times \frac{9}{16} = 9$

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