If $m$ is the slope of a line perpendicular to $3 x - 4 y - 8 = 0$ .Find the value of $9 m^{2}$

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Solution

Slope $= m = \frac{- c o - e f f i c i e n t o f x}{c o - e f f i c i e n t o f y} = \frac{- 3}{- 4} = \frac{3}{4}$
Slope of the perpendicuar line is $\frac{- 4}{3}$
$9 m^{2} = 9 \times \frac{- 4}{3} \times \frac{- 4}{3} = 9 \times \frac{16}{9} = 16$

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