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Question

If m is the slope of a tangent to the curve e2y=1+4x2 then


A

|m|<1

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B

|m|1

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C

|m|>1

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D

|m|1

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Solution

The correct option is D

|m|1


Taking log on both the sides, we get

2y=log(1+4x2)

Differentiating with respect to x, we get

2dydx=8x1+4x2

dydx=4x1+4x2

Since, 4x1+4x2 so |m|1


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