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Quantum Numbers

If ml= magn...

Question

If $m_{l} =$ magnetic quantum number and $l =$ azimuthal quantum number, then:

m_{l} = l + 2

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m_{l} = 2 l^{2} + 1

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l = \frac{m_{l} - 1}{2}

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l = 2 m_{l} + 1

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Solution

The correct option is C $l = \frac{m_{l} - 1}{2}$
For given azimuthal number $l$ magnetic quantum numbers can have values from $- l$ to $+ l$ including zero.

Total values of $m_{l} = 2 l + 1$

$∴ l = \frac{m_{l} - 1}{2}$

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Similar questions

n = 4, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}

n = 3, l = 1, m_{l} = 1, m_{s} = - \frac{1}{2}

n = 3, l = 2, m_{l} = 0, m_{s} = + \frac{1}{2}

n = 3, l = 0, m_{l} = 0, m_{s} = - \frac{1}{2}

n = 4, l = 2, m_{l} = - 2, m_{s} = - 1 / 2

n = 3, l = 2, m_{l} = 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{l} = 0, m_{s} = + 1 / 2

n = 3, l = 1, m_{l} = 1, m_{s} = - 1 / 2

m =

l =

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m_{l}

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