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If m = log ...

Question

If $m = log 20$ , $n = log 25$ and $2 log (x - 4) = 2 m - n$ , then the value of $x$ is equal to

A

12

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B

3

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C

8

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D

9

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Solution

The correct option is C $8$
$m = log 20 n = log 25 2 log (x - 4) = 2 m - n log {(x - 4)}^{2} = 2 log 20 - log 25 log {(x - 4)}^{2} = log (\frac{20^{2}}{25}) Removing log ({x - 4)}^{2} = \frac{20^{2}}{5^{2}} Taking square root x - 4 = \frac{20}{5} x - 4 = 4 ∴ x = 8$

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Similar questions

m = log 20

n = log 25

, then the value of

x

2 log (x - 4) = 2 m - n

If $m = l o g 20$ and $n = l o g 25$ , find the value of x, so that : $2 l o g (x - 4) = 2 m - n$ .

p = log 20

q = log 25

, find the value of

x

2 log (x + 1) = 2 p - q

m = \frac{1}{3 - \sqrt{8}}

n = \frac{1}{3 + \sqrt{8}}

m^{2}

17 + 6 \sqrt{n}

, then value of

n

2 log \frac{15}{8} - log \frac{25}{162} + 3 log \frac{4}{9}

log m

, then the value of

m

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