If m, $m_{n}$ and $m_{p}$ are the masses of $_{Z} X^{A}$ nucleus, neutron and proton respectively

m < (A - Z) m_{n} + Z m_{p}

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m = (A - Z) m_{n} + Z m_{p}

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m = (A - Z) m_{p} + Z m_{n}

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m > (A - Z) m_{n} + Z m_{p}

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Solution

The correct option is A $m < (A - Z) m_{n} + Z m_{p}$
The mass of nucleus formed is always less than the sum of the masses of the constituent protons and neutrons i.e. $m < (A - Z) m_{n} + Z m_{p}$ .

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Similar questions

m_{n}

m_{p}

_{Z} X^{A}

If m, $m_{n}$ and $m_{p}$ are the masses of $_{Z} X^{A}$ nucleus, neutron and proton respectively, then which of the following is correct?

m_{n}

m_{p}

m_{n}

m_{p}

_{Z} X^{A}

m_{p}

m_{n}

M

Z

N

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