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Question

If m, n are integers and x=cosα+isinα, y=cosβ+sinβ, then find xmyn+1xmyn.

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Solution

x=cosα+isinα=eiα
y=cosβ+isinβ=eiβ

xmyn+1xmyn=ei(mα+nβ)+1ei(mα+nβ)

ei(mα+nβ)+ei(mα+nβ)

=cos(mα+nβ)+isin(mα+nβ)+cos(mα+nβ)isin(mα+nβ)

=2cos(mα+nβ)

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