If $m * n = m + (m - 1) + (m - 2) + . . . . . . + (m - n)$ , evaluate $7 * 5$ .

25

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27

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18

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Solution

The correct option is C $27$
$\Rightarrow$ $m * n = m + (m - 1) + (m - 2) + . . . . + (m - n)$
$\Rightarrow$ In $7 * 5$ , $m = 7$ and $n = 5$
$\Rightarrow$ $7 * 5 = 7 + (7 - 1) + (7 - 2) + (7 - 3) + (7 - 4) + (7 - 5)$
$\Rightarrow$ $7 * 5 = 7 + 6 + 5 + 4 + 3 + 2$
$∴$ $7 * 5 = 27$

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If m∗n=m+(m−1)+(m−2)+......+(m−n), evaluate 7∗5.

The correct option is C 27⇒ m∗n=m+(m−1)+(m−2)+....+(m−n)⇒ In 7∗5, m=7 and n=5⇒ 7∗5=7+(7−1)+(7−2)+(7−3)+(7−4)+(7−5)⇒ 7∗5=7+6+5+4+3+2∴ 7∗5=27

If $m * n = m + (m - 1) + (m - 2) + . . . . . . + (m - n)$ , evaluate $7 * 5$ .

The correct option is C $27$
$\Rightarrow$ $m * n = m + (m - 1) + (m - 2) + . . . . + (m - n)$
$\Rightarrow$ In $7 * 5$ , $m = 7$ and $n = 5$
$\Rightarrow$ $7 * 5 = 7 + (7 - 1) + (7 - 2) + (7 - 3) + (7 - 4) + (7 - 5)$
$\Rightarrow$ $7 * 5 = 7 + 6 + 5 + 4 + 3 + 2$
$∴$ $7 * 5 = 27$