If√m+√n-√p=0, then prove that m+n-p=4mn.

Open in App

Solution

Given √m + √n = √p
square both sides: m + n + 2√(mn) = p
so m+n- p = - 2√(mn)
so (m + n - p)² = 4 m n

here power on the term m+n-p is 1 in yout question
but it is true only when (m+n-p)^2 in LHS

Suggest Corrections

Similar questions

\sqrt{m} + \sqrt{n} - \sqrt{p} = 0,

(m + n - p)^{2} = 4 m n

S_{n} = n^{2} p

S_{m} = m^{2} p, m \neq n

S_{p} = p^{3}

If $S_{n} = n^{2} p$ and $S_{m_{3}} = m^{2} p, m \neq n$ , in an A.P., prove that $S_{p} = p^{3}$ .

f (1) = 0

f (m + n) = f (n) + 3 (4 m n - 1)

Join BYJU'S Learning Program