If m= number of distinct rational numbers pq∈(0,1) such that p,q∈{1,2,3,4,5} and n= number of onto mappings from{1,2,3} onto{1,2}, then m−n is
A
1
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B
−1
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C
0
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D
3
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Solution
The correct option is D3
Rational number pqϵ(0,1), so numerator has to be less than denominator. To satisfy this condition we have the following :
for p=1; number of numbers pq are 4. for p=2, number of rational numbers are 3. for p=3; there are 2 numbers for p=4, there is only one number ∴m=4+3+2+1=10 Number of onto functions from (1,2,3) to (1,2) are total number of functions - number of into functions n=32−2=9−2=7 ∴m−n=10−7=3