Question

If $m$th terms of the series $63+65+67+69+.....$ and $3+10+17+24+....$ be equal, then $m=$

• A. $11$
• B. $12$
• C. $13$
• D. $15$

Answer 1

The correct option is C $13$

both are $A{P}^{\prime }s\Rightarrow$

$a_{m1}=a_{m2}$

$\Rightarrow 63+(m-1)2=3+(m-1)7$

$60=5(m-1)$

$12=m-1$

$13=m$